Answer:
a
Step-by-step explanation:
first one i believe
212°F
147°F
23.2 min
1) Initial temperature for t=0
T(0)=68+144e^(0)=68+144=212°F
2) After 15 min
T(15)=68+144e^(-0.04*15)=68+144e^(-0.6)=147°F
3) 125°F -> t=?
125=68+144e^(-0.04t)
144e^(-0.04t)=125-68=57
e^(-0.04t)=57/144=0.4 you can apply ln on both sides:
-0.04t=ln(0.4) solving you get t=23.3 min
Answer:
1. yes
2.no
3.yes
4. no
hope this helps I'm not sure about number 2 tho
Answer:
r = Q/(8s^2)
Step-by-step explanation:
Divide by the coefficient of r.
Q/(8s^2) = 8rs^2/(8s^2) = r
