Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
Step-by-step explanation:
-26a-19-35=-84
-26a-19+(19)-35=-84+(19)
-26a-35=-65
-26a-35+(35)=-65+(35)
-26a=-30
-26a/26=-30/26
Answer:
3 inches
Step-by-step explanation:
6 divded by 2 (or in half ) is 3
The area of the original polygon is:
A = 225 m ^ 2
The similar polygon area is:
A '= (k ^ 2) * (A)
Substituting values:
3 * 225 = (k ^ 2) * (225)
Clearing k we have:
k ^ 2 = 3
k = (3) ^ (1/3)
Answer:
The length of each side increased by:
k = (3) ^ (1/3)
Distribute and you will find 6(3)+6(-y)=18+(-6y)=18-6y
