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Oduvanchick [21]
2 years ago
15

Find x,, y and z in the following similar shapes. (Pls answer)

Mathematics
1 answer:
Troyanec [42]2 years ago
6 0

Answer:

Hi myself Shrushtee.

Step-by-step explanation:

x = 5

y = 8

z = 15

Simple

Please mark me as brainliest...

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Benny bought six new baseball trading cards to add to his collection . The next day his dog ate half of his collection. There ar
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90 because if his dog ate half his cards and benny had 45 left that means 45 times two equals 90 because the dog ate HALF of 90
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3 years ago
Which statement describes the value of the expression 4 * 18932 + 921
IceJOKER [234]
I'm confused, there are no statement. 
But <span>4 * 18932 + 921 is equal to 76,649.

4*18932+921
75728+921= 76649
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3 years ago
What is 3.504 estimate to
tatuchka [14]
3.504 estimates to 4
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3 years ago
Read 2 more answers
64 = 4(p + 2) + 24 please solve step by step
Wittaler [7]

Answer:

8

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant   1 • -16 = -16

Step-2 : Find two factors of  -16  whose sum equals the coefficient of the middle term, which is   6 .

     -16    +    1    =    -15

     -8    +    2    =    -6

     -4    +    4    =    0

     -2    +    8    =    6    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  8

                    p2 - 2p + 8p - 16

Step-4 : Add up the first 2 terms, pulling out like factors :

                   p • (p-2)

             Add up the last 2 terms, pulling out common factors :

                   8 • (p-2)

Step-5 : Add up the four terms of step 4 :

                   (p+8)  •  (p-2)

            Which is the desired factorization

3 0
3 years ago
Read 2 more answers
A positive integer from one to six is to be chosen by casting a die. Thus the elements c of the sample space C are 1, 2, 3, 4, 5
Alex_Xolod [135]

Answer with Step-by-step explanation:

We are given that six integers 1,2,3,4,5 and 6.

We are given that sample space

C={1,2,3,4,5,6}

Probability of each element=\frac{1}{6}

We have to find that P(C_1),P(C_2),P(C_1\cap C_2) \;and\; P(C_1\cup C_2)

Total number of elements=6

C_1={1,2,3,4}

Number of elements in C_1=4

P(E)=\frac{number\;of\;favorable \;cases}{Total;number \;of\;cases}

Using the formula

P(C_1)=\frac{4}{6}=\frac{2}{3}

C_2={3,4,5,6}

Number of elements in C_2=4

P(C_2)=\frac{4}{6}=\frac{2}{3}

C_1\cap C_2={3,4}

Number of elements in (C_1\cap C_2)=2

P(C_1\cap C_2)=\frac{2}{6}=\frac{1}{3}

C_1\cup C_2={1,2,3,4,5,6}

P(C_1\cup C_2)=\frac{6}{6}=1

4 0
3 years ago
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