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2 years ago

5

Literally anyone HELP

1 answer:

barxatty [35]2 years ago

6 0

Answer:

the answer is the last one, you solve this by comparing the lines from each shape. these shapes are congruent, meaning they're the same, so the like AB on the first shape and EF on the second are the same, and so on if that makes any sense. surely someone else could do a better explanation than me tho

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Alicia bikes 25% of a 100-mi trip on the first day. she bikes of the remaining distance on the second day. on the third day, she

DochEvi [55]

First day: 25% × 100 = 25 ( miles)
Second day : the remaining distance is 100 - 25 = 75 ( milesl
Third day: 40% × 75 = 30
25 + 75 + 30 = 130 (miles)

5 0

2 years ago

The sum of twice a number and five is 13. Find the number.

Eduardwww [97]

4

let the number be x

so by the question , 2x+5=13

solving this we get ,

2x=13-5

2x=8

so x=4

6 0

2 years ago

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Tom purchased a 40lb. bag of dog food. Knowing that there are 16 ounces in a pound, how many ounces of dog food are in the bag?

yan [13]

Answer:

640 Oz

Step-by-step explanation:

1 Lb = 16 Oz

40 Lb • 16 Oz = 640 Oz

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Mark brainliest

8 0

2 years ago

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According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h

andreyandreev [35.5K]

Answer:

The graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph $f(x)=x^2-4x+3$

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation $f(x)=x^2-4x+3$ the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, $f(x)=x^2-4x+3=0$

This is a quadratic equation, $x^2-4x+3=0$

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

$x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0$

$\Rightarrow x(x-1)-3(x-1)=0$

$\Rightarrow (x-3)(x-1)=0$

Using zero product property, $a\cdot b=0 \Rightarrow a=0\ or \ b=0$

$\Rightarrow (x-3)=0$ or $\Rightarrow (x-1)=0$

$\Rightarrow x=3$ or $\Rightarrow x=1$

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

3 0

2 years ago

Use the discriminant to find the number of real roots in Y = x^2 – 6x + 9

BaLLatris [955]

So discriminant is being counted from that equation:
b^2-4ac = 36-36 = 0

As discriminant is 0, then there is just 1 root -> -b/2a = 6/2 = 3.

4 0

2 years ago