Answer:
Solution
verified
Verified by Toppr
m
2
−3m−1=0
m
2
−3m=1 → (1)
Third term =(
2
1
coeeficientofm)
2
(
2
1
×(−3))
2
=(
2
−3
)
2
=
4
9
Adding
4
9
to both sides of equation (1), we get
m
2
−3m+
4
9
=1+
4
9
∴ m
2
−3m+
4
9
=
4
4+9
∴ (m−
2
3
)
2
=
4
13
Taking square roots on both sides
∴ m−
2
3
=±
2
13
∴ m=
2
3
+
2
13
or m=
2
3
−
2
13
m=
2
3+
13
,
2
3−
13
are the roots of the given quadratic equation.
Answer: if you had a circle of radius r, then the 2*radius is equal to the diagonal of the square. So the length of the side is calculated from the Pythagorean theorem since squares have right triangles in them: (2r)^2=2(l^2). Sqrt(2*r^2)=l where l is the length of the side of the square.
Step-by-step explanation:
Answer:
D is the true statement
Step-by-step explanation:
A
h(4)=13 and h(20)=13, so h(4)=h(20) and it is not true that h(4)<h(20)
B
This is untrue as we can see that the graph reaches its peak at h(12), so it would be symmetric about the line t=12, not t=10.
C
This is untrue as for all values of t less than 24, the height above the ground, h(t), is greater than zero.
D
This is true because as we can see from the table, when t values are equal distances from 12 (eg. 8 and 16), their h(t) values are the same.
Taking 20 away from 50 will result in 30
Juan should plant 16 cucumbers in each row.