Answer:

Step-by-step explanation:
The given equation 5y'' + 3y' - 2y =0 can be written as

Solving for complementary function we have Roots of
as follows


Thus the complementary function becomes
y=
where
are calculated roots
thus solution becomes

Now to solve for the coefficients we use the given boundary conditions

hence the solution becomes

Answer:
The answer is $13! Hope this helps!
Step-by-step explanation:
Assuming he works every week of the year. 40hrs a week×52 weeks a year=2,080 hours. $27,040 / 2,080 hours equals $13 an hour!
Answer:
D) the standard error for her sample is 15
Step-by-step explanation:
Samantha is 95% certain that between 50% and 70% of the first year students agree that they should be able to bring a car to campus.
Here
- 95% is the confidence level.
- The range between 50% and 70% indicates 95% confidence interval.
- 60% is the average proportion of the first year students at her university think they should be able to bring a car to campus.
- 10% (0.1) is the margin of error from the mean
Since standard error can be obtained by dividing margin of error by the z-statistic of the confidence level which is 1.96. The standard error for her sample
does not equal to 15.
Answer:
A. 11/36
Step-by-step explanation:
Add all the numbers together(36), and then see how many out of that number are the vibrant blue shirt. Since they are asking the probability of you being given a vibrant blue shirt, and there are 11 out of the 36 shirts, therefore you have an 11/36 chance that you will be given a vibrant blue shirt.
Answer:
He's correct.
Step-by-step explanation:
As long as there is no change in sign of the variables.