The answer is B. a_n = 7n+10
This strategy works because if you subtract one number from another the sum of the two numbers should be the that is being subtracted from. (In this case, it's 200)
Answer:
(x − 2) = 3
Remove the bracket
x - 2 = 3
Group the constants at one side of the equation
x = 2 + 3
x = 5
Therefore x = 5.00 to 3 significant figures.
Hope this helps
Remember:
a^m * a^n=a^(m+n)
a^-m=1/a^m
8³ x 8⁻⁵=8³⁻⁵=8⁻²=1/8²=1/64<1
Answer: the student is not correct, because 1/64<1, and 8³ x 8⁻⁵=1/64.
