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Maksim231197 [3]
3 years ago
15

Help! 15 points!

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
6 0

Answer: there called Valentine's day cookies

Step-by-step explanation: I know then I ate one before it was good you can get them at dollar General or at Wal-Mart.

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Simplify the expression (-7)2.
torisob [31]

Answer: -14

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can someone please solve 10n - 3 = 7n + 21
Ira Lisetskai [31]
10 n-3 = 7n+21

Add 3 to both sides :

10n-3+3=7n+21+3

10n=7n+24

Subtract  7 n from both sides:

10n-7n=7n+24-7n

3n=24

Divide both sides by 3 :

\frac{3n}{3} = \frac{24}{3}

n = 8

hope this helps!
6 0
4 years ago
I need to solve this using l'hopital's rule and logarithmic diferentiation.
arlik [135]

Yo sup??

For our convenience let h=x+1

therefore

when x tends to -1, h tends to 0

hence we can rewrite it as

\lim_{h \to \ 0 } (cos(h))^{(cot(h^2 )}

This inequality is of the form 1∞

We will now apply the formula

e^(^g^(^x^)^(^f^(^x^)^-^1^)^)

plugging in the values of g(x) and f(x)

e^{lim_{h \to \ 0}{(cot(h)^2(cos(h)-1))}

express coth² as cosh²/sinh² and also write cosh-1 as 2sin²(h/2)

(by applying the property that cos2x=1-sin²x)

After this multiply the numerator and denominator with h² so that we can apply the property that

\lim_{x \to \ 0 } sinx/x =1

Now your equation will look like this.

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2)*h^2)/(sin(h)^2*h^2)}

We will now apply the result

\lim_{x \to \ 0 } sinx/x =1

where x=h²

we get

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2)}

we now multiply the numerator and denominator with 4 so that we can say

\lim_{h^2 \to \ 0 } sin^2(h/2)/(h^2/4) = 1

e^{lim_{h \to \ 0}{((cos(h)^2(2sin^2(h/2))/(h^2*4/4)}

=e^{lim_{h \to \ 0}{((cos(h)^2*2)/(4)}

Apply the limits and you will get

e^{cos(0)^2*2/4

=e^{1/2}

Hope this helps.

7 0
3 years ago
Simplify 27- 9+(12-5)÷4 with solution ​
viktelen [127]

Answer:

It's 28 3/4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A student measures an angle that turns through 29 360 29360 of a circle. The student says the angle measures 29°. Is the student
sveta [45]
I think you have a typo in your problem. I believe you are asking about 29% of the circle. 

In that case, it would by 29% of 360 or 0.29 x 360 = 104.4

29% is not the same as 29 degrees.
7 0
4 years ago
Read 2 more answers
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