Answer:
The initial number is <u>-1218.321</u>.
Step-by-step explanation:
Let the initial number be 'x'.
The number 'x' is divided into 104.13.
So, we divide the number 'x' by 104.13. This gives,
Now, the quotient is multiplied by 4. So, this means we need to multiply 4 to the fraction above. This gives,
Now, 5 is added to the result. This gives,
Now, as per question:
Now, solving for 'x', we add -5 both sides. This gives,
Therefore, the initial number is -1218.321.
Answer:
because The perimeter of a rectangular playground can be no greater than 120 meters, The width of the playground cannot exceed 22 meters
=> the length of the playground cannot exceed: (120/2)-22= 38(meters)
Step-by-step explanation:
Answer:
y= -11/144(x-8)^2+6
Step-by-step explanation:
This equation can be represented in vertex form, which is:
y=a(x-h)^2+k
If we plug in 8 as h and 6 as k we get the following equation:
y=a(x-8)^2+6
Now we have to plug in x and y. We can use the other point (-4,-5) and plug it into the equation and get:
-5=a(-4-8)^2+6
Once we solve this we get a= -11/144
Now we have to plug in -11/144 into the original equation to get
y = -11/144 (x-8)^2 + 6
Answer:
A. The bag weights for brand A have less variability than the bag weights for brand B.
Step-by-step explanation:
In a box plot display, measure of variability can be determined by the length of the rectangular box or/and by the length of the whiskers.
The longer or greater the length, the more the variability the data set has. The shorter or smaller the length, the lesser the variability.
The box plot display of Brand A has shorter rectangular box and a shorter whisker length compared to the box plot display of Brand B. Therefore, it can be concluded that: bag weights for Brand A have less variability compared to bag weights for Brand B.
The correct statement of comparison is:
"A. The bag weights for brand A have less variability than the bag weights for brand B."
Option B is incorrect. Bag weights for Brand A do not have more variability than those of Brand B.
Option C and option D are both incorrect. Neither an outlier nor range can be used to represent or describe "typical value" for a given data set.
Typical bag weights can be well represented or described by average bag weights or median weight of the data set.
