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2 years ago

On the Fahrenheit scale, at what temperature does water boil?

Mathematics

2 answers:

Mkey [24]2 years ago

7 0

C at 212 degrees fahrenheit

Studentka2010 [4]2 years ago

5 0

C. 212 degrees Fahrenheit

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G=(z-s)/r solve for z

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Step-by-step explanation:

G = (z-s) ÷ r

G × r = (z- s)

Gr + s = z

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2 years ago

The scale of a model train is 1 inch to 13.5 feet. One of the cars of the model train is 5 inches long. What is the length, in f

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Mr. Jones is reading a mystery book to his sixth-grade English class. He reads 4 pages in 12 minutes.

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4, 8, 12, 16 I can’t see your table but I think these are the answers. :)

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Which statement is not true about the patter shown?

brilliants [131]

Answer:

Each fraction is greater than the previous fraction.

Step-by-step explanation:

Every statement is true except, the one that says "Each fracton is greater than the previous fraction." This statement is not true. I know it looks like it, but let's think about it. Each fraction is equivalent to 2/3, which means they are technically equal to each other. So that means that each fraction is not greater than the previous one. This means that the statement "Each fraction is equal to the previous fraction in the pattern multiplied by 2/2" is a true statement.

2/3 x 2/2 = 4/6

4/6 x 2/2 = 8/12

8/12 x 2/2 = 16/24

16/24 x 2/2 = 32/48

So that means that the next fraction in the pattern is indeed 32/48, making the last statement true.

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3 years ago

PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198

Elena-2011 [213]

The weight in 1980 is $\frac{4k}{5}$ kilograms

Solution:

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

To find: weight in 1980

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

The percentage increase is given by formula:

$\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100$

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

Substituting the values in formula,

$25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}$

Thus the weight in kilograms in 1980 is $\frac{4k}{5}$

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3 years ago