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Vika [28.1K]
2 years ago
10

Hello da 234234r32 ef3qew3e2wr3qefwasdwasd

Mathematics
1 answer:
scoray [572]2 years ago
3 0
Ah, thank you. your question truly made the most of sense.
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Serena has 3 necklaces, 6 pairs of earrings, and 4 bracelets in her jewelry box. How many different combinations of a necklace,
Ugo [173]
13 different combinations
4 0
3 years ago
Read 2 more answers
The diameter of a circle has endpoints A(1, 3) and B(4, 7), what is the
lana [24]

Answer:

The circumference of the circle is 5π

Step-by-step explanation:

First we need to calculate the diameter  

for this we have to know the distance between A(1, 3) and B(4, 7)

X =  Xb - Xa

X = 4 - 1

X = 3

Y = Yb - Ya

Y = 7 - 3

Y = 4

b - a = (3 , 4)

now that we have the distance of x and r we can calculate its distance using Pythagoras

h = hypotenuse

x = leg 1 = 3

y = leg 2 = 4

h² = x² + y²

we replace the known values

h² = (3)² + (4)²

h² = 9 + 16

h² = 25

h = √25

h = 5

The diameter of the circle is 5

Now we need to calculate the circumferencefor this we need to use the circumferenc formula of a circle:

c = circumference

d = diameter = 5

π = pi

c = π * d

we replace with the known values

c = 5  * π

c = 5π

The circumference of the circle is 5π

4 0
3 years ago
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
After the 4th half life how much of the sample is left if the mass is 100g.
vazorg [7]

Answer:

\huge\boxed{\sf 6.25 \ g}

Step-by-step explanation:

After every Half life , Half of the mass is left.

After 1st Half life = 100 g / 2 = 50 g

After 2nd Half life = 50 / 2 = 25 g

After 3rd Half life = 25 / 2 = 12.5 g

After 4th Half life = 12.5 / 2 = 6.25 g

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
2 years ago
What's the answer of 13846+8273636-3763x8273736
ipn [44]
13846+8273636
= 8287482

8287482-3763
=8283719

8283719x8273736
=6.8537304^13
7 0
3 years ago
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