All categories

3 years ago

Calculus application

Mathematics

1 answer:

Ugo [173]3 years ago

8 0

Answer:

49m/s

59.07 m/s

Step-by-step explanation:

Given that :

Distance (s) = 178 m

Acceleration due to gravity (a) = g(downward) = 9.8m/s²

Velocity (V) after 5 seconds ;

The initial velocity (u) = 0

Using the relation :

v = u + at

Where ; t = Time = 5 seconds ; a = 9.8m/s²

v = 0 + 9.8(5)

v = 0 + 49

V = 49 m/s

Hence, velocity after 5 seconds = 49m/s

b) How fast is the ball traveling when it hits the ground?

V² = u² + 2as

Where s = height = 178m

V² = 0 + 2(9.8)(178)

V² = 0 + 3488.8

V² = 3488.8

V = √3488.8

V = 59.07 m/s

You might be interested in

out of 30 questions on the maths test tomi knew the answer to 27 of them what percentage of questions did tomi know the answer f

Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

$\frac{27}{30} \times 100$

so after we cut the nessecary we get 90%

Hope this helps you

Mark as the brainlist

thank you

8 0

3 years ago

Frank has x baseball cards in his collection. He gets 45 more for his birthday. Write an expression to show the number of baseba

jasenka [17]

Answer:

Frank has X+45 baseball cards

Step-by-step explanation:

You just add 45 new baseball cards to the ones he had before which is X

5 0

3 years ago

Read 2 more answers

A rectangle has a length that is three feet more than twice it’s width. If the area of the rectangle is 90 square feet, then alg

Mkey [24]

Answer:

$Length=27feet\\Width=12 feet$

Step-by-step explanation:

Let, the length of the rectangle be 'L'

and, width of the rectangle be 'W'

length=2*Width+3

$L=(2W+3) feet\\\\$

Area of the rectangle= 90 square feet

Area of a rectangle = Length*Width

$90=(2W+3)*W\\\\2W^2+3W=90\\\\2W^2+3W-90=0\\\\$

Using Factorization Method to solve quadratic equation:

$2W^2-12W+15W-90=0$

Taking common from the equation:

$2W(W-12)+15(W-12)=90\\\\(W-12)(2W+15)=0\\\\W-12=0\\\\W=12 feet$

$2W+15=0\\\\2W=-15\\\\W=-7.5 feet$

The Width cannot be negative, therefore Width(W)=12 feet

$Length=2*Width+3\\\\=(12*2)+3\\\\=24+3\\\\=27 feet$

$Length=27feet\\Width=12 feet$

3 0

3 years ago

Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a

LekaFEV [45]

To make this a little clearer, let's give the pairs of inequalities the same denominator:

Question 1:
 $\frac{11}{15}$ ? $\frac{5}{7}$
First, apply the common denominator to the first fraction:
$(\frac{11}{15})7 \\ \frac{11}{15} * \frac{7}{7} \\ \frac{11*7}{15*7} \\ \frac{77}{105}$
Do the same for the second: $15( \frac{5}{7}) \\ \frac{5}{7}* \frac{15}{15} \\ \frac{5*15}{7*15} \\ \frac{75}{105}$
Nest, compare the two fractions:
$\frac{77}{105} \ \textgreater \ \frac{75}{105}$
Therefore:
$\frac{11}{15}$ > $\frac{5}{7}$

Question Two:
$\frac{5}{9}$ ? $\frac{7}{13}$
Apply the common denominator to fraction one:
$13( \frac{5}{9}) \\ \frac{5}{9} * \frac{13}{13} \\ \frac{5*13}{9*13} \\ \frac{65}{117}$
Fraction two:
$9(\frac{7}{13}) \\ \frac{7}{13} * \frac{9}{9} \\ \frac{7*9}{13*9} \\ \frac{63}{117}$
Evaluate:
$\frac{65}{117}$ > $\frac{63}{117}$
Therefore:
 $\frac{5}{9}$ > $\frac{7}{13}$

Hope this helps!

5 0

3 years ago

What is greater - 6 or 5

Tresset [83]

Answer:

5 is greater

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers