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3 years ago

You start at (1, -4). You move left 6 units. Where do you end?

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

4 0

Answer:

You will end up at (-5, -4)

Step-by-step explanation:

you find where (1, -4) is on the graph than from that point move left 6 units.

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Limitation of -4 to the left of the absolute value of x+4 divided by x+4

timama [110]

I believe you're asking about the one-sided limit,

$\displaystyle \lim_{x\to-4^-}\frac{|x+4|}{x+4}$

Recall the definition of absolute value:

• $|x| = x$ if $x\ge0$

• $|x| = -x$ if $x < 0$

Since we're approaching -4 from the left, we're effectively focusing on a domain of $x$ or $x+4$ . So, by the definition above, we have $|x+4| = -(x+4)$ . Then in the limit, we have

$\displaystyle \lim_{x\to-4^-}\frac{|x+4|}{x+4} = \lim_{x\to-4^-}\frac{-(x+4)}{x+4} = \lim_{x\to-4^-}(-1) = \boxed{-1}$

7 0

3 years ago

Find the range of the function. f(x) = -7x2 – 3 -

Irina-Kira [14]

Answer:

its x: x< -3

Step-by-step explanation:

8 0

3 years ago

enrollment in a photography class increased from 25 to 35 students. What was the percent of increase in enrollment?

ElenaW [278]

Answer

40%

Explanation

A parentage value is a value that has been compared to 100.

Percentage = (change in the value)/(the original value) × 100%

= (35-25)/25 × 100%

= 10/25 × 100%

= 40%

6 0

3 years ago

Read 2 more answers

Solve the following non-linear system of equations algebraically.

ExtremeBDS [4]

Answer:

x = -2

Step-by-step explanation:

since y is common in both equations, you can equate them to be equal

-2x² - 4x + 5 = 2x² + 4x + 5

4x² + 8x = 0

factor out 4x

4x(x + 2) = 0

divide both sides by 4x

x + 2 = 0

x = -2

6 0

4 years ago

1. A right triangle LMN is given where: side MN = 8 side NL (the hypotenuse) =

inessss [21]

Step-by-step explanation:

$\underline{ \underline{ \text{Given}}} :$

Length of MN ( Base ) = 8
Length of NL ( Hypotenuse ) = 10

$\underline{ \underline{ \text{To \: find}}} :$

Length of LM ( Perpendicular )

$\underline{ \underline{ \text{Using \: pythagoras \: theorem}}} :$

$\boxed{ \sf{ {Hypotenuse}^{2} = {Perpendicular}^{2} + {Base}^{2} }}$

⤑ $\sf{ Perpendicular = \sqrt{ {(Hypotenuse)}^{2} - {(Base)}^{2} } }$

⤑ $\sf{ \sqrt{ {(10)}^{2} - {(8)}^{2} } }$

⤑ $\sf{ \sqrt{100 - 64}}$

⤑ $\sf{ \sqrt{36}}$

⤑ $\boxed{ \sf{6\: units}}$

$\pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline { \tt{6 \: units}}}}}}}$

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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5 0

3 years ago