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pentagon [3]
3 years ago
6

Leslie has a watering can that holds 3 liters of water. She uses 250 milliliters of water on each of her plants. How many plants

can she water? Enter your answer in the box.
Mathematics
2 answers:
arsen [322]3 years ago
8 0

Answer:

12

Step-by-step explanation:

1,000 milliliters in a liter. 3 liters, so divide 3,000 by 250, which will give you 12. she can water 12 plants.

mafiozo [28]3 years ago
6 0

Step-by-step explanation:

Lester can water 12 plants because there is 1000 milliliters in one liter so if we do 1000x3=3000÷250=12 plants being able to get watered

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53

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1,2,3 or 4<br> Thank you!
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Option 3

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To find differences in the angles of the intersections we must know how many degrees each angle corresponds to. We must also take into account that the sum of the internal angles must equal 180°.

<h3>What is a triangle?</h3>

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5 0
2 years ago
What type of number is<br> -15/3
Oduvanchick [21]

Answer:

Rational

Step-by-step explanation:

Rational numbers can be reduced to a fraction

Irrational numbers cannot be reduced to a fraction

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6 0
3 years ago
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
3 years ago
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