Solve for g and h please
1 answer:
You might be interested in
Answer:
A. (-1, -4)
Step-by-step explanation:
The vertex can be found by converting the equation from standard form to vertex form.
<h3>Vertex</h3>Considering the x-terms, we have ...
y = (x^2 +2x) -3
where the coefficient of x is 2. Adding (and subtracting) the square of half that, we get ...
y = (x^2 +2x +(2/2)^2) -3 -(2/2)^2
y = (x +1)^2 -4
Compare this to the vertex form equation ...
y = a(x -h)^2 +k
which has vertex (h, k).
We see that h=-1 and k=-4. The vertex is (h, k) = (-1, -4).
On the attached graph, the vertex is the turning point, the minimum.
The tangent line to the curve has slope equal to . Use implicit differentiation to find this derivative.
The given line in slope-intercept form is
and has slope -9/2. Any line parallel to this one has the same slope. The tangent to the hyperbola has this slope at points (<em>x</em>, <em>y</em>) such that
Find the points on the hyperbola where this condition is met.
Then use the point-slop formula to build the equations of these tangents: