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Ber [7]
3 years ago
9

An integer is chosen at random from 1 to 50 inclusive. Find the probability that the chosen integer is not divisible by 2, 7, or

9.
A. 13/50
B. 16/25
C. 9/25
Mathematics
1 answer:
Crank3 years ago
6 0

Answer:

13/50

Step-by-step explanation:

The probability is 13/50.

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The price of a ticket to a play is $50 per person. On Monday afternoons, the theater reduces the ticket price to $35 per
Anvisha [2.4K]

Answer:

40%

Step-by-step explanation:

7 0
3 years ago
I need help no links please only for question c and a tyy
user100 [1]

Answer:

A) 75 C) 20

Step-by-step explanation:

A) multiply the 25 questions by 3 to get the highest score possible since you would get them all correct. 25 x 3 = 75

C) Multiply 3 by 10: 3 x 10 = 30 He missed 5 so multipy 5 and 2: 5 x 2 =10 30 - 10 = 20

7 0
3 years ago
Read 2 more answers
Y=Mx+B what would m be
PIT_PIT [208]
M would represent the slope. for example if your equation was y=5x+9, 5 is your slope and 9 is the y intercept
4 0
4 years ago
Q20-23 with steps pls
just olya [345]

20: Let x be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30

Rearrange the left hand side as

\dfrac{4x-3x}{24}=30

And multiply both sides by 24 to get

x=720

21: Let M and J be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

M=3J+11

If they both get 9 more marbles, Mike will have M+9 marbles, and Judy will have J+9 marbles. So, we have

M+J+18=93 \iff M+J=75 \iff M=75-J

Plug this value in the first equation and we have

75-J=3J+11 \iff 4J=64 \iff J=16

And we deduce

M=16\cdot 3 + 11=59

So, the difference is  

M-J=59-16=43

22: Let x,y,z be the number of $10, $20 and $50 coupon, respectively. We're given:

\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}
We can write the third equation by substituting the expressions for x and z:
[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38

Rearrange as follows:

(2y+3)+y+\left(\dfrac{1}{2}y\right)=38 \iff \dfrac{7}{2}y=35 \iff 7y=70 \iff y=10

And now we can deduce the number of the other coupons:

x=2\cdot 10+3=23,\quad z=\dfrac{1}{2}\cdot 10=5

So, the total value is

23\cdot 10+10\cdot 20+5\cdot 50=230+200+100=530

23:  a) In order to find the first three terms of the sequence, you just need to plug n=1,2,3:

a_1=4\cdot 1+3=7,\quad a_2=4\cdot 2+3=11,\quad a_3=4\cdot 3+3=15

b) We have

a_r = 4r+3=71 \iff 4r=68 \iff r=\dfrac{68}{4}=17

c) 105 is a term of the sequence if and only if there exists an integer k such that

a_k=4k+3=105 \iff 4k = 102 \iff k=\dfrac{102}{4}=25.5

So, 105 is not a term of the sequence.

8 0
4 years ago
4 times (12-8) + 2^3. (2 to the 3rd power)
brilliants [131]

Answer:

It's 48. Heres why:

Step-by-step explanation:

Our equation, I believe, is 4[(12-8) + 2³]. We can do the operations in the parenthesis:

4[(4)+8] (12-8 = 4, and 2³ is 8). If we add 4 + 8, we get 12. Multiply 12 by 4, we get 48.

5 0
3 years ago
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