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muminat
3 years ago
14

Can somebody help me please first person to asnwer gets brainliest

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Answer:

a= 15

a18= 267

Step-by-step explanation:

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A department store is having a sale in which every item is 38% off its original price. The regular price of a suit is $112. How
lara [203]

Answer: $42.56

Step-by-step explanation:

Percent discount in department store = 38%

The regular price of suit = $112.

Price taken off the regular price of the suit =

38% of $112

So, 38% of $112

= (38/100) x $112

= 0.38 x $112

= $42.56

(i.e the customer will pay $112 - $42.56 = $69.44 only for the suit)

Thus, the price taken off the regular price of the suit is $42.56

3 0
3 years ago
Seven times a number minus the number is -48.
DENIUS [597]
Same as the other one :) if u thought my answers were helpful to you please mark me as brainliest :)

5 0
3 years ago
Read 2 more answers
What is the sum of the complex numbers 3 − 4i and 5 + 3i ?
Mandarinka [93]

Answer:

8 - i

General Formulas and Concepts:

<u>Algebra I</u>

  • Combining Like Terms

<u>Algebra II</u>

  • Standard Form: a + bi

Step-by-step explanation:

<u>Step 1: Define</u>

(3 - 4i) + (5 + 3i)

<u>Step 2: Simplify</u>

  1. Combine like terms (Z):                    8 - 4i + 3i
  2. Combine like terms (i):                      8 - i
7 0
3 years ago
What is the radius of a sphere with a volume of 1/6 pie
Yakvenalex [24]

Answer:

\large\boxed{the\ radius\ R=\dfrac{1}{2}}

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

We have

V=\dfrac{1}{6}\pi

Substitute:

\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi        <em>divide both sides by π</em>

\dfrac{4}{3}R^3=\dfrac{1}{6}          <em>multiply both sides by 3</em>

3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}

4R^3=\dfrac{1}{2}          <em>divide both sides by 4</em>

R^3=\dfrac{1}{2}:4\\\\R^3=\dfrac{1}{2}\cdot\dfrac{1}{4}\\\\R^3=\dfrac{1}{8}\to R=\sqrt[3]{\dfrac{1}{8}}\\\\R=\dfrac{\sqrt1}{\sqrt8}\\\\R=\dfrac{1}{2}

3 0
3 years ago
Let f(x) = sin(x) + icos(x). Show that |f(x)| = 1.
Oksanka [162]
F(x) = sin(x) + icos(x)
|f(x)| = sqrt(sin^2(x) + cos^2(x)) = sqrt(1) = 1

Therefore, |f(x)| = 1
5 0
3 years ago
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