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Natasha2012 [34]
2 years ago
9

If (k+1), 3k, (4k+2) are three consecutive terms of an AP then k = ?​

Mathematics
1 answer:
seropon [69]2 years ago
5 0

The three consecutive terms in an AP are (k+1) ,3k and (4k+2)

We know that

If a,b,c are the three consecutive terms in an AP then b = (a+c)/2

now ,

Let a = k+1 , b = 3k and c = 4k+2

⇛3k = (k+1+4k+2)/2

⇛3k = (5k+3)/2

⇛2×3k = 5k+3

⇛6k = 5k+3

⇛ 6k-5k = 3

⇛ k = 3

The value of k = 3

<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> if there consecutive terms of an AP are k+2 ,4k -6 and 3k-2 . What is the value of k....

brainly.com/question/23844186?referrer

the first three terms of an arithmetic sequence are 3k-1, 4k+1, 6k-2. What is the value of k?...

brainly.com/question/17447469?referrer

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