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Svetllana [295]
3 years ago
7

If you live in a rectangular city that is 1 mile along the southern border and contains 1000 people, what is the density of peop

le in the city?
Group of answer choices

A. We cannot calculate this value.

B. 1000 people per square mile

C. 1 person per square mile

D. 100 people per square mile
Mathematics
1 answer:
Setler [38]3 years ago
7 0

Answer:

The answer is B, which means the density is 1,000 people per square mile.

Step-by-step explanation:

This is true because there are 1,000 people on the one-mile-long southern border.

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(2^(3)*(-2)^(3)*3^(3))/(2^(3*2)*4^(4(-2))*8^(3))=?
TEA [102]

Answer:

-3456

Step-by-step explanation

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3 years ago
What is the first step to simplify the expression 64^42-[2(4-6)2]?
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Simplify what's in brackets first, then move to what's in the parenthesis
3 0
3 years ago
Find two positive angles and two negative angles that are coterminal with the given angle and less than 1080 but greater than 72
ivann1987 [24]

Answer:

The correct answer is 450°, 810°, -270° and -630°.

Step-by-step explanation:

According to the given scenario, the calculation of the two positive angles and two negative angles i.e. coterminal is as follows:

The coterminal angles are the angles in which the difference could be 360 degrees or the multiples of 360 degrees

For 90 degrees, the two positive angles are

a. 90° + 360°

= 450°

450° + 360°

= 810°

b. The two negative angles are

= 90° - 360°

= -270°

-270° - 360°

= -630°

3 0
3 years ago
F(x)=x^3+3
lawyer [7]

Answer:

  (a)   -3/4

  (b)  -0.75

  (c)  -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

  • evaluating the function at the midpoint of the bracketing interval
  • choosing a smaller bracketing interval
  • identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

__

(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

__

(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

__

(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

__

See the attached table for function values.

_____

<em>Comment on bisection iteration</em>

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.

5 0
3 years ago
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