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lesya [120]
3 years ago
13

Prove the identity cot^2x/cscx+1=1-sinx/sinx

Mathematics
1 answer:
Furkat [3]3 years ago
6 0
Cot²x/csc+1
=(csc²x-1)/(csc+1)

=((1/sin²x)-1)/((1/sinx)+1)

=((1-sin²x)/sin²x)/((1+sinx)/sinx)

=(1-sin²x)/(1+sinx)

=(1+sinx)(1-sinx)/sinx(1+sinx)

=(1-sinx)/sinx
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Subtract the sum of (3/5+1/5i) and (4/5-2/5i) from (9/5-1/5i). The result is
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<span>Subtract the sum of (3/5+1/5i) and (4/5-2/5i) from (9/5-1/5i). 
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