Prove the identity cot^2x/cscx+1=1-sinx/sinx
1 answer:
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Answer:
5th term of sequence = -18
nth term of the sequence = -5n + 7
Step-by-step explanation:
Difference between successive and previous term of the output,
= -3 - 2
= -5
Similarly,
= -5
There is a common difference 'd' = (-5)
Therefore, the sequence formed will be an arithmetic sequence.
First term of the sequence 'a' = 2
Explicit formula of an arithmetic sequence, = a + (n - 1)d [n = input value]
= 2 + (n - 1)(-5)
= 2 - 5n + 5
= -5n + 7
5th term of this sequence,
= 2 - 20
= -18
Therefore, 5th term of sequence = -18
nth term of the sequence = -5n + 7