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Tpy6a [65]
3 years ago
8

Y = r + 1 4y = 40 + 4

Mathematics
2 answers:
andrew-mc [135]3 years ago
7 0

Answer:

r = 10

y = 11

Step-by-step explanation:

4y = 40 + 4

4(r + 1) = 40 + 4

4(r) + 4(1) = 40 + 4

4r + 4 = 40 + 4

4r + 4 = 44

4r + 4 - 4 = 44 - 4

4r = 40

4r ÷ 4 = 40 ÷ 4

r = 10

-----------------------------------------

y = r + 1

y = (10) + 1

y = 11

-----------------------------------------

4y = 40 + 4

4(11) = 40 + 4

4(11) = 44

44 = 44

strojnjashka [21]3 years ago
5 0

Answer:

Step-by-step explanation:

Move all terms that don't contain

x

to the right side and solve.

x

=

20

−

2

y

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3. Which linear equation corresponds to the line graph?
iogann1982 [59]

Answer:

Y=1/3x

Step-by-step explanation:

1) there is no y intercept as x=0 when y=0 so that rules out y=x-2

2) next, we will use the formula for slope to find the value of m

Y2-Y1/X2-X1

Where y2=-1

Y1=0

X2=-3

X1=0

So

-1-0/-3-0=-1/-3

Aka 1/3

So y=1/3x

Hope this helps!

3 0
3 years ago
Please show your work
Paladinen [302]

Answer:

see in the picture, the perimeter of this rectangle is

2( x + 3x) = 8x but the perimeter is 65.6

=> 8x = 65.6

<=> x = 65.6/8

=> x = 8.2

7 0
3 years ago
Solve: 3x - 7 - 2x + 5 = 6 A) -8 B) - 18 5 C) 4 D) 8
seropon [69]

Answer:

D) 8

Step-by-step explanation:

3x - 7 - 2x + 5 = 6

3x - 2x  = 6 + 7 - 5

  x   = 8

Note: 6 + 7 -5 =  13 -5 = 8

7 0
3 years ago
Increase 47 litres by 5%
Morgarella [4.7K]
49.35 litres

47 times 1.05=49.35

(Sheldon got it right first)
5 0
3 years ago
Read 2 more answers
Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
3 years ago
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