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murzikaleks [220]
3 years ago
10

2/9 x s = 1/2 I don’t know

Mathematics
1 answer:
WITCHER [35]3 years ago
3 0

Answer:

\frac{9}{4}

Step-by-step explanation:

\frac{2}{9}  \times s =   \frac{1}{2}  \\   \\  \frac{2s}{9}  =  \frac{1}{2}  \\ cross \: multiply \\ 9 \times 1 = 2s \times 2 \\ 9 = 4s \\ divivde \: both \: sides \: by \: 4 \\  \frac{9}{4}  =  \frac{4s}{4}  \\ s =  \frac{9}{4}

hope you understand

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Answer:

<em>(3*105 )+(2*104 )+(0*103) +(4*102 )+(0*101 )+(0*100)</em>

Step-by-step explanation:

(3*105 )

+(2*104 )

+(0*103)

+(4*102 )

+(0*101 )

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Find the area of a triangle with sides 8 equals 5 b equals 8 and C equals 11
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Write a polynomial function f of least degree that has a leading coefficient of 1 and the given zeros. Write the function in sta
NeX [460]

Answer:

f(x)=x^3+(3+\sqrt{5})x^2+(6\sqrt{5}-18)x

or

f(x)=x^3+3x^2+\sqrt{5}x^2-18x+6\sqrt{5}x

Step-by-step explanation:

A polynomial function with 3 zeroes is going to be of degree 3, so we're going to have at least least 3 factors of the form x-a, where <em>a </em>is a zero of the function. For three zeroes <em>a</em>, <em>b</em>, and <em>c</em>, we'd have the factors x-a,\ x-b, and x-c, making our function look like

f(x)=(x-a)(x-b)(x-c)

Substituting our roots for a, b, and c:

f(x)=(x-(-6))(x-0)(x-(3-\sqrt{5}))\\=(x+6)(x)(x-3+\sqrt{5})

To write this function in standard form, we can expand from left to right:

f(x)=(x^2+6x)(x-3+\sqrt{5})\\=(x^2+6x)x-(x^2+6x)3+(x^2+6x)\sqrt{5}\\=x^3+6x^2-3x^2-18x+\sqrt{5}x^2+6\sqrt{5}x\\=x^3+3x^2+\sqrt{5}x^2-18x+6\sqrt{5}x

At this point, we could either leave it as is, or group the coefficients for the x^2 and x terms to get

f(x)=x^3+(3+\sqrt{5})x^2+(6\sqrt{5}-18)x

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Answer:

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