A line that passes which two points would be parallel to a line with a slope of 3/4?

Mathematics

1 answer:

GalinKa [24]2 years ago

6 0

Answer:

lo que yo se es la b

Step-by-step explanation:

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4^x+7 = 8^2x-3 Solve each equation showing work please

RUDIKE [14]

If 4=2^2

8=2^3

(2^)2x+10=(2^)6x

(2^)6x-(2^)2x=10

(2^)2x×7=10, where x has no real value

3 0

3 years ago

Find (r-s) (t-s) + (s-r) (s-t) for all numbers r, s, and t. (a) 0 (b) 2 (c) 2rt (d) 2(s-r) (t-s) (e) 2(r-s) (t-s)

lyudmila [28]

Notice that the 2 expressions have 2 common terms.

(r-s) is just (s-r) times (-1)

similarly

(t-s) is just (s-t) times (-1)

this means that :

(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)

the 2 minuses in the first multiplication cancel each other so we have:

-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)

Answer:

d)2(s-r) (t-s)

3 0

3 years ago

Read 2 more answers

A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th

Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

$\tan\theta=\frac{Perpendicular}{base}$