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3 years ago

-0.05w=14 what property did you use

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

6 0

Answer:

280.

Step-by-step explanation:

-0.05×14= 280 280× -0.05=280

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You buy 1 1/4 yards of fabric and an $8 clothing pattern. Your total cost with a 6% sales tax added is $18.55. What is the cost

Paraphin [41]

First we can divide it by 106 then multiply it by 100 to get rid of the 6% sales tax, which now the cost of the stuff is $17.50.
Next, we subtract 8 from this to represent the clothing pattern cost. Now it is $9.50.
The last stap to this is to divide it by 1 1/4 to get the final cost per yard:
The fabric costs $7.60 per yard. Hope this helps!

8 0

4 years ago

Which of the following equations has no solution?

soldier1979 [14.2K]

Answer:

B. 3x+5−4x=−(x+8)

Step-by-step explanation:pls mark me

3 0

3 years ago

Read 2 more answers

A consumer organization estimates that over a 1-year period 20% of cars will need to be repaired once, 8% will need repairs

Sladkaya [172]

Answer:

Probability that a car need to be repaired once = 20% = 0.20

Probability that a car need to be repaired twice = 8% = 0.08

Probability that a car need to be repaired three or more = 2% = 0.02

a) If you own two cars what is the probability that neither will need repair?

Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair= $0.7 \times 0.7=0.49$

b) both will need repair?

Probability both will need repair = $0.3 \times 0.3=0.09$

c)at least one car will need repair

Neither car will need repair= $0.7 \times 0.7=0.49$

Probability that at least one car will need repair= 1-0.49 = 0.51

6 0

3 years ago

the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle

nikdorinn [45]

$l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}$
$length\approx9.71cm;\ width\approx17.71cm$

4 0

3 years ago

What is the range of the data below? 100 105 110 115 120 125 A 2 B 5 C 12 D 13

MrMuchimi

Answer:

ifk

Step-by-step explanation:

8 0

3 years ago