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mr_godi [17]
2 years ago
11

Please help question 4

Mathematics
1 answer:
Burka [1]2 years ago
3 0

Answer:

40 miles

Step-by-step explanation:

let distance be d and time be t

Since d varies directly with t, then the equation relating them is

d = kt ← k is the constant of variation

To find k use the condition d = 75 when t = 3

k = \frac{d}{t} = \frac{75}{3} = 25

d = 25t ← equation of variation

when t = 1.6, then

d = 25 × 1.6 = 40 miles

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A government bureau publishes annual price figures for new mobile homes. A simple random sample of 36 new mobile homes yielded t
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Answer:

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The prices in thousands of dollar are:</em>

<em>66.6, 69.8, 58.4, 57.3, 63.1, 61.8, 56, 72.7, 61.8,  </em>

<em>66.9, 72.6, 63.1, 58.7, 65.9, 61.1, 56.1, 49.9, 72.6,  </em>

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<em>56.4, 75.4, 76.3, 60.5, 74.6, 57, 69.2, 62.7, 77.2.</em>

<em />

We have a sample of n=36 new mobile homes.

The mean of this sample is:

M=(1/36)\sum_{i=1}^{36}x_i=\dfrac{2273.3}{36}=63.147

The population standard deviation is σ=7.5 (in thousands of dollars).

The critical value of z for a 99.7% CI is z=2.97.

Then, we can calculate the margin of error as:

E=z\cdot \sigma/\sqrt{n}=2.97*7.5/\sqrt{36}=22.275/9=2.475

Now we can calculate the lower and upper bound of the confidence interval as:

LL=\bar X-E=63.147-2.475=60.672\\\\UL=\bar X+E=63.147+2.475=65.622

The 99.7% confidence interval for the mean price of all new mobile homes is ($60,672, $65,622).

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