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2 years ago

Please help question 4

Mathematics

1 answer:

Burka [1]2 years ago

3 0

Answer:

40 miles

Step-by-step explanation:

let distance be d and time be t

Since d varies directly with t, then the equation relating them is

d = kt ← k is the constant of variation

To find k use the condition d = 75 when t = 3

k = $\frac{d}{t}$ = $\frac{75}{3}$ = 25

d = 25t ← equation of variation

when t = 1.6, then

d = 25 × 1.6 = 40 miles

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eduard

You can find the area of the rectangle and the triangle separately and then add them together which would result in 330in. I personally do not think you should use the trapezoid formula even though they said it is a trapezoid (a trapezoid is usually not shaped like that) but if you want to it would result in 270in.

3 0

2 years ago

could you possibly help me with this question? (its not part of a graded assignment, just a review from an online course of mine

Virty [35]

Let:

x = Pounds of walnuts in the mix.

Each pound of walnuts costs $0.80. thus x pounds of walnuts cost 0.8x dollars.

Each pound of cashews costs $1.25 and the mix will contain 8 pounds of cashews, so the cost is 8*$1.25 = $10

The total cost of the mix is, therefore: 0.8x + 10 dollars.

We are also given the pound of mix costs $1.00 and we have a total of 8 + x pounds, so the total cost of the mix is 1*(8 + x) dollars.

Equating both costs:

0.8x + 10 = 1*(8 + x)

Operating:

0.8x + 10 = 8 + x

Subtracting x and 10:

0.8x - x = 8 - 10

Simplifying:

-0.2x = -2

Dividing by -0.2:

x = -2/(-0.2)

x = 10

Answer: 10 pounds

8 0

1 year ago

192 is what percent of 600

morpeh [17]

Answer:

32%

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Por favor ayúdeme con mi tarea de matemáticas... Son ecuaciones<br> 2x + 4y=10<br> -x+5=9

Hatshy [7]

X+2y-5=0
x=-4

-x=9-5
-x=4
x=-4

3 0

2 years ago

Read 2 more answers

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

2 years ago