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finlep [7]
3 years ago
7

Which type of data is shown below? apple, 0.85 banana, 0.90 peach, 1.50

Computers and Technology
1 answer:
d1i1m1o1n [39]3 years ago
4 0

Answer:

dictionary data

Explanation:

data = {"apple" : 0.85, "banana" : 0.90, "peach": 1.50}

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Ksivusya [100]

<u>Answer:</u>

<em>int fNumber,scndNumber = -1,  </em>

<em>dup = 0; </em>

<em>do { </em>

<em>cin >> fNumber; </em>

<em>if ( scndNumber == -1) { </em>

<em>scndNumber = fNumber; </em>

<em>} </em>

<em>else { </em>

<em>if ( scndNumber == fNumber ) </em>

<em>duplicates++; </em>

<em>else </em>

<em>scndNumber = fNumber; </em>

<em>} </em>

<em>} while(fNumber > 0 );  </em>

<em>cout << dup; </em>

<u>Explanation:</u>

Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>

<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.

4 0
3 years ago
Read 2 more answers
Which statement regarding socializers is true?
allochka39001 [22]

Answer:

The answer is: they are comparable to suit of hearts

Explanation:

The answer is: they are comparable to suit of hearts

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computer has a 32-bit instruction word broken into fields as follows: opcode, six bits; two register file address fields, five b
lina2011 [118]

Answer:

a.  2^6, or 64 opcodes.

b.  2^5, or 32 registers.

c. 2^16, or 0 to 65536.

d.  -32768 to 32768.

Explanation:

a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.

b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.

c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.

d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.

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