The solution of the system of equations is (-3 , -2)
Step-by-step explanation:
Steps for Using Linear Combinations Method)
- Arrange the equations with like terms in columns
- Analyze the coefficients of x or y
- Add the equations and solve for the remaining variable
- Substitute the value into either equation and solve
∵ 3 x - 8 y = 7 ⇒ (1)
∵ x + 2 y = -7 ⇒ (2)
- Multiply equation (2) by 4 to make the coefficients of y are equal in
magnitude and different in sign
∴ 4 x + 8 y = -28 ⇒ (3)
Add equations (1) and (3)
∵ 3 x - 8 y = 7 ⇒ (1)
∵ 4 x + 8 y = -28 ⇒ (3)
∴ 7 x = -21
- Divide both sides by 7
∴ x = -3
Substitute the value of x in equation (2) to find y
∵ x + 2 y = -7 ⇒ (2)
∵ x = -3
∴ -3 + 2 y = -7
- Add 3 to both sides
∴ 2 y = -4
- Divide both sides by 2
∴ y = -2
The solution of the system of equations is (-3 , -2)
Learn more:
You can learn more about the system of the linear equations in brainly.com/question/13168205
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See picture below for a geometric view.
Let x = height of building
We use basic trigonometry to find x.
The tangent function = opposite side of right triangle OVER adjacent side of right triangle.
tan(2°) = x/1
Solve for x.
After multiplying both sides by 1 (here 1 represents 1 mile), we get
tan(2°) = x.
We now use the calculator to find x.
In fact, you can take it from here. Use your calculator.
Given:
side lengths of right triangles = 12 cm ; 16 cm ; 20 cm
lateral area = 192 cm²
lateral area of a triangular prism = perimeter * height
192 cm² = (12 cm + 16 cm + 20 cm) * height
192 cm² = 48 cm * height
192 cm² / 48 cm = height
4 cm = height
The height of the pedestal in the shape of a triangular prism is 4 cm.
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
Answer:
I got 31,529.8281
Step-by-step explanation:
I just replaced minimum with one(if i can do that).
If it's not right sorry.
