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3 years ago

Do you find this with synthetic and long divison?

Mathematics

1 answer:

yulyashka [42]3 years ago

8 0

Answer:

p=-2

Step-by-step explanation:

we can solve by both methods

if it is divisible by x-1,then remainder is zero.

i solve by synthetic division.

x-1=0,x=1

1 | 1 -1 p 2

| 1 0 p

_________

1 0 p |2+p

Here 2+p is remainder.

p+2=0

p=-2

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Which situation represented by 25/9 ?

faltersainse [42]

Answer:

the answer is 2.7777

Step-by-step explanation:

You just divide!

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3 years ago

Solve the equation:<br><br> x3−20=−15

stich3 [128]

Answer:

x = 1.71

Step-by-step explanation:

$x^3-20=-15\\x^3=-15+20\\x^3=5\\\sqrt[3]{x^3} =\sqrt[3]{5} \\x=1.71$

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3 years ago

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ASAP!! Three consecutive numbers have a sum of 156. What are the 3 numbers?

ryzh [129]

For this problem, all you need to do is find the three #'s that add up to 156.

So, lets look at the answers and add them up.

A. 50, 52, 54

50 + 52 + 54 = 156

B. 51,52,53

51 + 52 + 53 = 156

C. 49,50,51

49 + 50 + 51 = 150

D. 49,51,53

49 + 51 + 53 = 153

We get the answers (50,52,54) and (51,52,53)

Now, consecutive numbers are numbers that in order, like 1,2,3.

Therefore, the answer is (51,52,53)

3 0

3 years ago

Can someone help me with this

Solnce55 [7]

Aye man , who wants to give me points

4 0

2 years ago

Which applies the power of a product rule to simplify (5 t) cubed?

Elena L [17]

Answer:

(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed ⇒ 3rd answer

Step-by-step explanation:

Let us revise some rules of exponents

$a^{m}$ × $a^{n}$ = $a^{m+n}$

$a^{m}$ ×÷ $a^{n}$ = $a^{m-n}$

$(a^{m})^{n}$ = $a^{m.n}$

$(a.b)^{m}$ = $a^{m}$ . $b^{m}$

To simplify $(5t)^{3}$

∵ 5t means 5 × t

∵ Both of them are cubed

- Use the 4th rule above

∴ $(5t)^{3}$ = $(5)^{3}.(t)^{3}$

∵ (5)³ = 5 × 5 × 5 = 125

∴ $(5t)^{3}$ = $(5)^{3}.(t)^{3}$ = 125 t³

(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed

3 0

3 years ago

Read 2 more answers