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Salsk061 [2.6K]
3 years ago
12

LAST ONEEE <333333 HELPP

Mathematics
2 answers:
iragen [17]3 years ago
6 0
A.
explanation: 4 units down is negative and everything else is postive and 1 unit to the right is a postive because you’re moving in a postive direction.
Snowcat [4.5K]3 years ago
5 0

A

Step-by-step explanation:

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Given that D(x)=2 select all of the following that are true statements
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\bold{\huge{\underline{ Solution\: 2 }}}

  • The name of the circle is <u>IJKL</u>
  • The name of central Angle
  • \sf{\underline{= {\angle} IHJ }}
  • The name of the secant = <u>KL</u>

{\bigstar}Circle :- It is a round figures, which has no end points.

{\bigstar} Central angle :- It the angle ,which lie in the middle of the circle.

  • Here, H is the mid point of the circle .So, Angle IHJ is the central angle.

{\bigstar} Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .

  • Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

\bold{\huge{\underline{ Solution\: 3 }}}

  • Semicircle = FGH and FIH
  • Minor Arc :- FG or GH
  • Major Arc :- FHG or GFH

{\bigstar} Semicircle :- Semicircle is nothing but the half of the circle.

<u>Here</u><u>, </u><u>In </u><u>second </u><u>diagram </u>

  • FGH and FIH are acting as two semicircles which simulatineously forming one circle.

{\bigstar} Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.

<u>Here</u><u>, </u>

  • FG or GH are the minor arc of the given circle.

{\bigstar} Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.

<u>Here</u><u>, </u>

  • FHG or GFH is the major arc as it is larger than the semicircle of the given circle .
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2 years ago
What is | 5x + 8 | = x?
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For the first equation, I put it in y=mx+b form, so y=-3x-9
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3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Consider the gi
STatiana [176]

Answer:

To determine the inverse of the given function, change f(x) to y, switch x and y and solve for y and f^{-1}(x)= \frac{ln\ x+4}{2}

Step-by-step explanation:

Data provided in the question

f(x) = e^2x - 4

Now

to find the inverse let

So,

y = e^2x - 4

Now

Replace x and y

Therefore

x = e^2y - 4

Now compute the value of y

So,

x + 4 = e^2y

Now take ln on both sides:

The equation is

ln(x+4) = ln(e^2y)

ln(x+4) = 2y

y = ln(x+4) ÷ 2

f^{-1}(x)= \frac{ln\ x+4}{2}

Therefore,  To determine the inverse of the given function, change f(x) to y, switch x and y and solve for y and f^{-1}(x)= \frac{ln\ x+4}{2}

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3 years ago
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