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3 years ago

Help 20 points + brainiest answer

Mathematics

1 answer:

katovenus [111]3 years ago

7 0

2½ = 5/2

(2½ water)/(⅓ juice) = (5/2 water)/(⅓ juice) = (5/2) × (3/1) water/juice = (15/2) water/juice

(1⅔ water)/(¼ juice) = (5/3 water)/(¼ juice) = (5/3) × (4/1) water/juice = (20/3) water/juice

15/2 = 45/6
20/3 = 40/6
45/6 > 40/6
Clare uses more water. Han’s juice tastes stronger.

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Convert 4800 inches to feet

Mars2501 [29]

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3 years ago

Read 2 more answers

What percent of 150 is 162

Novay_Z [31]

To find a percentage of a number, you divide by that number.
So to find what percent of 150 162 is, you divide 162 by 150
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3 years ago

Gary is 8 years older than his brother. Six years ago Gary was three times as old as his brother. How old are they now?

Yuliya22 [10]

Answer:Gary-18 years brother-10 years

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2nd case:......

3rd case:.....

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8 0

4 years ago

Which information can always be read directly from an equation written in point-slope form?

Mariulka [41]

Answer:

The location of a point on the line

Step-by-step explanation:

Generally, we can write an equation in the point slope form as follows;

y-y1 = m(x-x1)

Where m is the slope of the line

So looking at the option, we can easily see that the information we can read directly from the point-slope form is the location of a point on the line.

We can easily tell the value of (x1,y1) which easily gives out the location of that point on the line

3 0

4 years ago

Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used

ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes head start

Senn needs to give Ms. Beetle 18.4 minutes head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0

3 years ago