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tigry1 [53]
3 years ago
12

Solve each proportion 3/39= y/13

Mathematics
2 answers:
Sphinxa [80]3 years ago
6 0

Answer:

y = 1

Step-by-step explanation:

\frac{3}{39}  =  \frac{y}{13}

Cross multiply

39 = 39y

Divide by 39

y = 1

g100num [7]3 years ago
5 0

Answer:

\boxed {\boxed {\sf y=1}}

Step-by-step explanation:

To solve the proportion, we must solve for the variable. This is done by isolating the variable.

\frac {3}{39}= \frac {y}{13}

The variable, y, is being divided by 13. The inverse of division is multiplication. Multiply both sides of the proportion by 13.

13*\frac {3}{39}= \frac {y}{13}*13

13*\frac {3}{39}=y\\1=y

Another way to solve is by cross multiplying. Multiply the 1st numerator by the 2nd denominator, then the 1st denominator and the 2nd numerator.

\frac {3}{39}= \frac {y}{13}

3*13=39*y\\39=39y

Divide both sides by 39 to isolate the variable.

39/39=39y/39 \\1=y

In this proportion, y is equal to 1.

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Answer:

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3 years ago
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Based on the figure below, the ratio of x/y is equivalent to which trigonometric function?
Ede4ka [16]

Answer: OPTION D.

Step-by-step explanation:

For this exercise it is important to remember the following Trigonometric  Functions:

sin\alpha =\frac{opposite}{hypotenuse}\\\\cos\alpha =\frac{adjacent}{hypotenuse}\\\\tan\alpha =\frac{opposite}{adjacent}\\\\sec\alpha =\frac{hypotenuse}{adjacent}\\\\csc\alpha =\frac{hypotenuse}{opposite}\\\\cot\alpha =\frac{adjacent}{opposite}

Knowing this, we can identify that:

cosA=\frac{AC}{AB}=\frac{x}{AB}\\\\sinB=\frac{AC}{AB}=\frac{x}{AB}\\\\secA=\frac{AB}{AC}=\frac{AB}{x}\\\\tanB=\frac{AC}{BC}=\frac{x}{y}

Therefore, the ratio \frac{x}{y} is equivalent to this Trignometric function:

tanB=\frac{x}{y}

8 0
4 years ago
The equation of a line given two points needs to be found. Samuel claims that slope-intercept form will generate the equation an
Nikitich [7]

Answer:

Helena is correct.

Step-by-step explanation:

The slope intersept form of the line is

y = m x + c

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The point slope form of the equation is

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8 0
3 years ago
Use ΔABC shown below to answer the question that follows:
topjm [15]

Answer:

The correct options are a and b.

Step-by-step explanation:

It is given that triangle ABC with segment AD drawn from vertex A and intersecting side BC.

Two triangle are called similar triangle if their corresponding sides are proportional or the corresponding interior angle are same.

To prove ΔABC and ΔDBA are similar, we have to prove that corresponding interior angles of both triangle as same.

If segment AD is an altitude of ΔABC, then angle ADB is a right angle.

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\angle BAC=90^{\circ}

In triangle ΔABC and ΔDBA

\angle ABC\cong \angle DBA              (Reflexive property)

\angle BAC\cong \angle BDA              (Right angles)

By AA rule of similarity ΔABC and ΔDBA are similar.

Therefore correct options are a and b.

3 0
3 years ago
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sasho [114]

Answer:

A

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