Answer:
Step-by-step explanation:
The resulting course vector (magnitude 300, angle = 160° with the positive x axis (= 290° bearing)) with components (300cos160,300sin160) is the sum of the vector of the actual flight vector and the wind vector.
The wind vector has magnitude 18 and direction 46° with the positive x-axis ( it blows from - 134° with the positive x axis (= 224° bearing) into direction 46° with the positive x-axis). So its components are (18cos46,18sin46).
The course that the plane has to steer is :
(300cos160,300sin160)-(18cos46,18sin46)
=(300cos160 - 18cos46, 300sin160 - 18sin46)
=(-294.41, 89.6579)
The magnitude of this steering vector is = 307.749 knots and its direction will be:
with the negative x-axis (286.94° bearing).
Thus, the drift angle will be=290° - 286.94° = 3.06°.
All of these equations will be set up as: h(t) = +v₀t + h₀ where g represents gravity, v₀ represents initial velocity, and h₀ represents initial height. When working with ft/sec, g = 32. So, -g/2 = -16
1a) Length of time to reach its maximum height means you are looking for the x-value of the vertex (aka Axis Of Symmetry).
h(t) = -16t² + 160t
AOS: x = = = 5
Answer: 5 sec
1b) Length of time to fall to the ground means you are looking for the x-intercept when height (y-value) = 0.
h(t) = -16t² + 160t
0 = -16t² + 160t
0 = -16t(t - 10)
0 = -16t 0 = t - 10
t = 0 t = 10
t = 0 is when it started, t = 10 is when fell to the ground.
Answer: 10 sec
2c) Same concept as 1a
h(t) = -16t² + 288t
AOS: x = = = 9
Answer: 9 sec
2d) Same concept as 1b
h(t) = -16t² + 288t
0 = -16t² + 288t
0 = -16t(t - 18)
0 = -16t 0 = t - 18
t = 0 t = 18
Answer: 18 sec
3e) Same concept as 1a
h(t) = -16t² + 352t
AOS: x = = = 11
Answer: 11 sec
3f) Same concept as 1b
h(t) = -16t² + 352t
0 = -16t² + 352t
0 = -16t(t - 22)
0 = -16t 0 = t - 22
t = 0 t = 22
Answer: 22 sec
Answer:
Hullo how can I help?
Step-by-step explanation:
5n^2 is the greatest common factor
Answer:
<em>x∈ -10,4</em>
Step-by-step explanation:
x+3<7, x+3≥0: -(x+3)<7, x+3<0- separate the inequality into 2 possible cases
x<4, x≥-3; x>-10, x<-3- solve the inequalities
x∈ [-3,4}; x∈ {-10,-3}- find the intersection
x∈{-10,4}- Find the union