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SCORPION-xisa [38]
3 years ago
10

S’tone anyone know this by chance ?!!!

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

Answer: 3

Step-by-step explanation:

You might be interested in
For the linear function f(x) = 7x - 4, find the range of f(x) at x = -2,0, and 2.
kenny6666 [7]

Answer:

(-2, -18) and (2, 10)

Step-by-step explanation:

the answer is -18 and 10

8 0
4 years ago
Please help
Andreyy89

9514 1404 393

Answer:

  y -1 = -1(x -2)

Step-by-step explanation:

The slope of the line through the two points can be found from the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (5 -1)/(-2 -2) = 4/-4 = -1

The point-slope equation for a line through point (h, k) with slope m is ...

  y -k = m(x -h)

You have (h, k) = (2, 1) and m = -1. Putting these values into the form gives ...

  y -1 = -1(x -2)

_____

<em>Additional comment</em>

Your problem statement already has two of the three values filled in, so you only need to enter the x-coordinate of the first point: 2.

5 0
3 years ago
Part A: The area of a square is (16x2 − 8x + 1) square units. Determine the length of each side of the square by factoring the a
d1i1m1o1n [39]

Answer:

see below

Step-by-step explanation:

16x^2 − 8x + 1

(4x)^2 -8x +1

Factor

This is a perfect square trinomial

a^2 -2ab +b^2 = (a-b)(a-b)

(4x)^2 -8x +1 = (4x-1) (4x-1)

The area of a square is given by

A = s^2

(4x-1) ^2 = s^2

4x-1 = s

The side length is 4x-1

(81x^2 − 4y^2)

(9x)^2 - (2y)^2

This is the difference of squares

a^2 - b^2 = (a-b) (a+b)

(9x-2) (9x+2)

The area of a rectangle is

A = l*w

(81x^2 − 4y^2)  = (9x-2) (9x+2)

The dimensions are (9x-2) (9x+2)

3 0
3 years ago
Can someone please help me?
Vladimir79 [104]

Answer:

<h3> ( - 1 , - 1 )</h3>

Option D is the correct option.

Step-by-step explanation:

y = - 2x - 3 → Equation ( i )

y = 3x + 2 → Equation ( ii )

Using elimination method

y + 2x = - 3

y - 3x = 2

---------------------

5x = - 5

Divide both sides of the equation by 5

\frac{5x}{5}  =  \frac{ - 5}{5}

Calculate

x =  - 1

Again, Putting the value of x in equation ( ii ) in order t get the value of y

y = 3x + 2

plug the value of x

= 3  \times ( - 1) + 2

Any expression multiplied by ( - 1 ) equals it's opposite

=  - 3 + 2

Calculate

=  - 1

Therefore, The possible solution of the system is the ordered pair ( x , y )

(x \:, y \: ) =  ( - 1 \:, - 1)

-----------------------------------------------------------------------

Check if the given ordered pair is the solution of the system of equation

- 1 =  - 2 \times ( - 1)  - 3

- 1 = 3 \times ( - 1) + 2

Simplify the equation

- 1 =  - 1

- 1 =  - 1

Since all the equalities are true, the ordered pair is the solution of the system.

<h3>( x , y ) = ( - 1 , - 1 )</h3>

Hope this helps..

Best regards!!

7 0
3 years ago
Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number
sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable <em>X</em> is:

E(X)=\sum x\cdot P(X=x)

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner:   1           2           3          4           5              6

Amount earned (<em>X</em>):   $1        $4         $7        $10     -$8.75     -$8.75

Probability:                 1/6       1/6         1/6        1/6         1/6           1/6

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x\cdot P(X=x)

         =(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})

         =\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}

         =\frac{1+4+7+10-8.75-8.75}{6}

         =0.75

Thus, the expected value of playing the game is $0.75.

5 0
3 years ago
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