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Nonamiya [84]
3 years ago
11

F(x) = 4x+3x g(x) = 2x-5 7. Find (f+9) (x) 8. Find (f - g) (x)

Mathematics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

7. (f+g)(x) = 6x - 2

8. (f-g)(x) = 2x + 8

Step-by-step explanation:

We are given two function, f(x) and g(x).

We want to find their addition and their subtraction, and we do this combining like terms.

The functions are:

f(x) = 4x + 3

g(x) = 2x - 5

7. Find (f+9) (x)

4x + 3 + 2x - 5 = 4x + 2x + 3 - 5 = 6x - 2

So

(f+g)(x) = 6x - 2

8. Find (f - g) (x)

4x + 3 - (2x - 5) = 4x + 3 - 2x + 5 = 4x - 2x + 3 + 5 = 2x + 8

So

(f-g)(x) = 2x + 8

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snow_tiger [21]

Step-by-step explanation:

To find a rat of change (ROC) you take the two numbers and the two prices and subtract them to make a ratio<u>:</u>

<u>_</u><u>_</u><u>_</u><u>_</u><u>6</u><u>-</u><u>3</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u> = <u>_</u><u>_</u><u>_</u><u>3</u><u>_</u><u>_</u><u>_</u>

$2.56-$2.44 = $2.12

The reduce to the lowest number (the 3 to a 1)

<u>_</u><u>_</u><u>3</u><u>_</u><u>_</u><u>_</u> = <u>_</u><u>_</u><u>_</u><u>1</u><u>_</u><u>_</u>

$2.12 $0.71

The ROC is $0.71

8 0
4 years ago
Read 2 more answers
I need help plz i need help
Marrrta [24]
To estimate, you can round each decimal to the nearest whole number, and then add them up together to get a number close to the real answer.

I hope this helps! :)
7 0
3 years ago
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The cost of 1 m ribbon is ₹ 75. Find the cost of 7/5 metres of ribbon​
Margaret [11]

Given that

The cost of 1 m ribbon = Rs.75

The cost of 7/5 m ribbon

→ (7/5)×75

→ (7×75)/5

→7×15

→₹ 105

The cost of 7/5 m ribbon is ₹105.

8 0
3 years ago
Which is the correct way to solve the given equation
Karolina [17]

Option 2. x = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} shows the correct way to use the quadratic formula to solve the given equation.

Step-by-step explanation:

Step 1:

For an equation of the form ax^{2} +bx+c=0 the solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Here a is the coefficient of x^{2}, b is the coefficient of x and c is the constant term.

x^{2} -4x=21 can also be written as x^{2} -4x-21=0.

Comparing x^{2} -4x-21=0 with ax^{2} +bx+c=0, we get that a is 1, b is -4 and c is -21.

To get the solution, we substitute the values of a, b, and c in x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

Substituting the values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}= \frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.

\frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.

This is option 2.

7 0
4 years ago
Can someone help me on this pls i will give brainliest
Dmitrij [34]
His error is in step 3. The variable x is being multiplied by -7 and therefore he should have divided both sides by -7, not 7 as he did.
8 0
3 years ago
Read 2 more answers
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