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Andrews [41]
4 years ago
10

Which is the correct way to solve the given equation

Mathematics
1 answer:
Karolina [17]4 years ago
7 0

Option 2. x = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} shows the correct way to use the quadratic formula to solve the given equation.

Step-by-step explanation:

Step 1:

For an equation of the form ax^{2} +bx+c=0 the solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Here a is the coefficient of x^{2}, b is the coefficient of x and c is the constant term.

x^{2} -4x=21 can also be written as x^{2} -4x-21=0.

Comparing x^{2} -4x-21=0 with ax^{2} +bx+c=0, we get that a is 1, b is -4 and c is -21.

To get the solution, we substitute the values of a, b, and c in x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

Substituting the values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}= \frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.

\frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.

This is option 2.

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