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Korvikt [17]
3 years ago
10

Find the value of x.

Mathematics
1 answer:
marta [7]3 years ago
8 0

Answer:

\boxed {\boxed {\sf x=5}}

Step-by-step explanation:

We are given a quadrilateral. It will be difficult to find x using this shape, but we can drop a perpendicular line and create a right triangle (refer to the attached image).

Match up the other sides. The height is equal to 4.

At the base, the longer portion is 7 because the line segment above the base is 7. Since the entire base is 10, the smaller portion must be 3 because 10-7=3.

Now we have 2 sides of a right triangle and one unknown. We can use the Pythagorean Theorem.

a^2+b^2=c^2

Where <em>a</em> and <em>b</em> are the legs and <em>c</em> is the hypotenuse.

In this triangle, 4 and 3 are the legs because they make the right angle. x is the hypotenuse because it is opposite the right angle.

  • a= 4, b=3, c=x

Substitute the values into the formula.

(4)^2+(3)^2=x^2

Solve the exponents.

  • (4)²= 4*4= 16

16+(3)^2=x^2

  • (3)²= 3*3= 9

16+9=x^2 \\

25=x^2

Take the square root of both sides of the equation to isolate the variable.

\sqrt{25} =\sqrt{x^2}

5=x

<u>x is equal to 5. </u>

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Answer:

a) 23.11% probability of making exactly four sales.

b) 1.38% probability of making no sales.

c) 16.78% probability of making exactly two sales.

d) The mean number of sales in the two-hour period is 3.6.

Step-by-step explanation:

For each phone call, there are only two possible outcomes. Either a sale is made, or it is not. The probability of a sale being made in a call is independent from other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours, find:

Six calls per hour, 2 hours. So

n = 2*6 = 12

Sale on 30% of these calls, so p = 0.3

a. The probability of making exactly four sales.

This is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{12,4}.(0.3)^{4}.(0.7)^{8} = 0.2311

23.11% probability of making exactly four sales.

b. The probability of making no sales.

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.3)^{0}.(0.7)^{12} = 0.0138

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c. The probability of making exactly two sales.

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{12,2}.(0.3)^{2}.(0.7)^{10} = 0.1678

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d. The mean number of sales in the two-hour period.

The mean of the binomia distribution is

E(X) = np

So

E(X) = 12*0.3 = 3.6

The mean number of sales in the two-hour period is 3.6.

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