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guajiro [1.7K]
2 years ago
10

You know whats up, please help me ahha.

Mathematics
1 answer:
Rom4ik [11]2 years ago
4 0

Answer:

0.07

Step-by-step explanation:

     0.07  - quotient

  ____

4/0.28     - divided

l

divisor

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If the length of a rectangle is 5 feet and a height of 3 feet what is the area of the rectangle
choli [55]

Answer:

15feet squared

Step-by-step explanation:

Area= Length x height

= 5x3

= 15feet squared

4 0
3 years ago
Read 2 more answers
Find the values of x and y. <br> x + 7i = y − yi
lys-0071 [83]

Answer: X = y - yi - 7i

               Y = (x + 7i)/(1 - i)

Step-by-step explanation: for the case of (X) you only need to pass the 7i to the other side with the subtraction sign (-7i), then we get this equation:

x + 7i = y − yi

X = y - yi - 7i

in the case of the (Y), first we select the common multiple.

y - yi = y(1 - i)

if we replace it in the original expression, we get the following equation:

x + 7i = y(1 - i)

after that you can pass the value (1 - i) to the other side dividing,

Y = (x + 7i)/(1 - i)

6 0
3 years ago
Read 2 more answers
a wall is 2m at one end and 2.4m at the other end. the area of the wall is 26.4m squared. what is the length of the wall?
andrew11 [14]
Since the height is different on both ends, we can assume that the wall is a trapezoid. Knowing that, we can replace the measures we know in the formula and our onky variable is the length of the wall - we only need to isolate it. A= ((b+B)h)/2 26.4=((2+2.4)h)/2 52.8=4.4h h=12
6 0
3 years ago
PLEASE HELP ASAP ASAP
muminat

Answer:

slope = -1/12

Step-by-step explanation:

From the figure we can see that the line passes through 2 points which are

(-6,-1) and (6,-2)

Use the formula y2-y1/x2-x1

(-2-(-1))/6-(-6)

(-2+1)/6+6

-1/12

3 0
2 years ago
Consider two vectors A and B A=14i and B= -4i+8j
DaniilM [7]
Assuming \mathbf a,\mathbf b\in\mathbb R^3, you have

\mathbf a\cdot\mathbf b=(14)(-4)+(0)(8)=-56

so

((\mathbf a\cdot\mathbf b)\,\mathbf i)\cdot\mathbf a=(-56\,\mathbf i)\cdot(14\,\mathbf i)=(-56)(14)=-784

Next,

\mathbf a+\mathbf b=(14\,\mathbf i)+(-4\,\mathbf i+8\,\mathbf j)=10\,\mathbf i+8\,\mathbf j

Then

(\mathbf a+\mathbf b)\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\10&8&0\\-4&8&0\end{vmatrix}=112\,\mathbf k

((\mathbf a+\mathbf b)\times\mathbf b)\times\mathbf k=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&112\\0&0&1\end{vmatrix}=\mathbf 0
4 0
3 years ago
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