3 years ago

Write an equation of a line that passes through 2,0 and is the perpendicular to the line y=-1/2x +3

Mathematics

1 answer:

AURORKA [14]3 years ago

8 0

9514 1404 393

Answer:

y = 2x -4

Step-by-step explanation:

The coefficient of x in the given equation is the slope of the line. A perpendicular line will have a slope that is the opposite reciprocal:

-1/(-1/2) = 2

The point-slope form of the equation of a line can be used to find the desired equation:

y -y1 = m(x -x1) . . . . . . line through (x1, y1) with slope m

For (x1, y1) = (2, 0) and m = 2, the equation is ...

y -0 = 2(x -20

y = 2x -4

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If f(x) = 2x+4, which of the following is the inverse of f(x)?

creativ13 [48]

Answer:

${f}^{ - 1} (x)= \frac{x}{2} - 2$

Step-by-step explanation:

The given function is

$f(x) = 2x + 4$ Let

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Interchange x and y.

$x = 2y + 4$

Solve for y,

$x - 4 = 2y$

Divide both sides by 2

$y = \frac{x}{2} - 2$

Therefore;

${f}^{ - 1} (x)= \frac{x}{2} - 2$

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