Answer:
18
Step-by-step explanation:
24*.75=18
Answer:
B
Step-by-step explanation:
The differences in the terms of f(x) are + 3, + 5, + 7
Since the differences are not constant the relationship is not linear
Note the differences in the differences are + 2, + 2,
The second differences are constant indicating a quadratic relationship
Note the relationship between x and f(x)
x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)
x = 2 → 2² = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)
x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)
x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)
Thus f(x) = x² + 5 → B
(x4−3x3+4x2−8)/(x+1) = x3−4x2<span>+8x−8.</span>
<span>You can probably just work it out.
You need non-negative integer solutions to p+5n+10d+25q = 82.
If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80.
So this is the same as n + 2d + 5q ≤ 16
So now you simply have to "crank out" the cases.
Case q=0 [ n + 2d ≤ 16 ]
Case (q=0,d=0) → n = 0 through 16 [17 possibilities]
Case (q=0,d=1) → n = 0 through 14 [15 possibilities]
...
Case (q=0,d=7) → n = 0 through 2 [3 possibilities]
Case (q=0,d=8) → n = 0 [1 possibility]
Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81
Case q=1 [ n + 2d ≤ 11 ]
Case (q=1,d=0) → n = 0 through 11 [12]
Case (q=1,d=1) → n = 0 through 9 [10]
...
Case (q=1,d=5) → n = 0 through 1 [2]
Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42
Case q=2 [ n + 2 ≤ 6 ]
Case (q=2,d=0) → n = 0 through 6 [7]
Case (q=2,d=1) → n = 0 through 4 [5]
Case (q=2,d=2) → n = 0 through 2 [3]
Case (q=2,d=3) → n = 0 [1]
Total from case q=2: 1 + 3 + 5 + 7 = 16
Case q=3 [ n + 2d ≤ 1 ]
Here d must be 0, so there is only the case:
Case (q=3,d=0) → n = 0 through 1 [2]
So the case q=3 only has 2.
Grand total: 2 + 16 + 42 + 81 = 141 </span>
Answer:
-6F
Step-by-step explanation: It would be 5F(4hr) = 20F. So if you have 14F subtract 20F you get -6F. Hope this helped.
