Answer:
8-5 times R
Step-by-step explanation:
you subtract 8-5 to get that answer and then you do less than twice the number r i think this is correct hope it helps :)
Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.
Subtract 16 from both sides.
Divide by 4 on both sides.
The length of line segment PQ is 5 units.
Answer:
15. 50 kg
16a. 5 kg
16b. 3.75 kg
Step-by-step explanation:
The formula relating force, mass, and acceleration can be solved for mass. This formula will apply to both problems. We'll use m for both "mass" and "meters". We presume you can avoid getting mixed up by understanding that meters is used in the context of acceleration: m/s².
F = ma
m = F/a . . . . . divide by a
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15. m = (250 N)/(5 m/s²) = 50 kg
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16a. m = (15 N)/(3 m/s²) = 5 kg
16b. m = (15 N)/(4 m/s²) = 3.75 kg
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<em>Comment on units</em>
Especially for physics problems, I like to keep the units with the numbers. It is helpful to remember that Newtons are equivalent to kg·m/s². So, dividing Newtons by acceleration in m/s² will give mass in kg. Since you're familiar with F=ma, it's not too hard to remember that the units of force (N) are the product of the units of mass (kg) and acceleration (m/s²).
