It’s -0.5 because it an integer has to be whole number hope this helps :)
OPTION:
B
Step-by-step explanation:
<span>The length of an arc, L = theta/360 * 2 * pie * r
Where theta = 81 and r = 10ft = 3.048m
So length = 81/360 * 2 * pie * 3.048
L = * 0.225 * 2 * pie * 3.048
L = 1.37 * pie
L = pie. Option A</span>
√29/2 since cotangent deals the reciprocal of tangent and cotangent value is adjacent side/opposite side
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
