Answer:
The statement is true
Step-by-step explanation:
To answer this question we must take the limit of f(x) when the function tends to 1. We must take this limit by the right and the left of 0. . If any of these limits tends to infinity then the function is discontinuous at x = -1.
But if the
<em>Where b is a real number</em>
Then the function is continuous at x = -1
Then.
and
Then:
Therefore the function is continuous at x = -1. The statement is true
5.) y=7/8x+1
6.)y=-10x
7.) y=2.5x-7
8.)y=1.2x
9.) y=-5x-8
Answer with Step-by-step explanation:
We are given that
We have to prove that why the limit x approaches 0(csc(x)-cot(x)) involves an indeterminate form and prove that the limit equals to 0.
Because and
We know that cos 0=1 and sin 0=0
Substitute the values then we get
We know that is indeterminate form
Hence, the limit x approaches 0(csc(x)-cot(x)) involves an indeterminate form.
L'hospital rule:Apply this rule and differentiate numerator and denominator separately when after applying we get indeterminate form
Now,using L' hospital rule
because
Now, we get
Hence,
Ce clasă ești sa văd daca te pot ajuta
<span>the highest common factor is forty-five</span>