ANSWER
EXPLANATION
The boundary line passes through (-2,2) and (0,-2).
The slope of this line is
The y-intercept is , c=-2.
The slope-intercept form of this line is given by;
We substitute values to obtain;
Since the lower half-plane is shaded the required inequality is
Answer: Substitution
Step-by-step explanation:
GIVEN:
y=3x
2x+4y=12
Then, 2x+4(3x)=12
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Substitution: replacing one variable in terms of another variable.
As we can see from the given aspects, y=3x, and the conclusion expression has no y instead of 3x. This means it represented y in terms of x, which fits the definition of substitution that replaces one variable.
Hope this helps!! :)
Using f(x) = y, we know that a graph of the function contains the (x,y) points (2,5) and (6,-1). first find the slope of that line,
m = (y2 - y1)/(x2 - x1) ⇒ -6/4⇒-3/2
then using either point (I'll use the first one) solve for b in y = mx + b.
5 = (-3/2)(2) + b⇒ 5 = -3 + b⇒ 8 = b.
So y = (-3/2)x + 8 ⇒ f(x) = (-3/2)x + 8.
Answer:
True, false, true, true.
Step-by-step explanation:
The roots zeros of a quadratic function are the same as the factors of the quadratic function. This is true because your roots are your factors—>(x-3) is a factor, x=3 is the root.
The roots zeros are the spots where the quadratic function intersects with the y-axis. No! Those are called y-intercepts!
The roots zeros are the spots where the quadratic function intersects with the x-axis. True. X-intercepts are your solutions. (x-3) graphed would the (3,0). That’s a solution.
There are not always two roots/zeros of a quadratic function, True. No solution would be when your quadratic doesn’t intersect the x-axis. One solution would be when your vertex would be on the x-axis. Two solutions is when your quadratic intersects the x-axis twice. Can there be infinite solutions? No. It’s either 0, 1, or 2 solutions.
