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3 years ago

MATH HELP LEASE WILL GIVE BRAINLIEST!!!

Mathematics

1 answer:

Marysya12 [62]3 years ago

8 0

The answer is (22) hope it helps have a great day

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

eduard

1.) 3x

2.) area

3.) six

4.) 3/2

8 0

3 years ago

8x=64 how do I solve this

Drupady [299]

Divide both sides by 8

4 0

3 years ago

Read 2 more answers

The recycling bin in the shape of a rectangular prism is 15.5 inches long, 8 inches wide and 7 inches high. The recycling bins n

Viktor [21]

Answer:

694 cubic inches

Step-by-step explanation:

Dimension of prism

Length = 15.5 inches

width = 8 inches

height = 7 inches

Volume of regular prism is given by area of base * height

area of base = length * width ( as bin is rectangular)

area of base = 15.5 * 8 square inches = 124 square inches

Volume of regular prism = area of base * height

= 124 * 7 cubic inches = 868 cubic inches

_________________________________________________

868 cubic inches is the full capacity of the recycling bin

it is given that recycling bins need to be emptied when it is 80% full

so we need to find the 80% capacity of recycling bin

80% capacity of recycling bin = 80/100 * full capacity of the recycling bin

= 0.8 * 868 cubic inches = 694.4 cubic inches

694.4 cubic inches is the amount needed before the recycle bin is ready to empty .

But question says answer should in nearest cubic inch

hence answer is 694 cubic inches

3 0

3 years ago

I don’t get this at all, can someone please help

JulsSmile [24]

Answer:

m = 44

Step-by-step explanation:

USe the pythagoream thyroem a^2 + b^2 = m^2. so 10^2 + m = 12^2

or 100 + m = 144. subtract 100 from both sides, you get m = 44

6 0

2 years ago

a theater is designed with 15 seats in the first row, 19 in the second, 23 in the third, and so on. if this seating pattern cont

marusya05 [52]

Answer:

<u>131 seats</u> are in the 30th row.

Step-by-step explanation:

The theater is designed with the first row there are 15 seats, in second row 19 seats and in the third row there are 23 seats.

Now, to find the number of seats in the 30th row.

So, we get the common difference( $d$ ) from the arithmetic sequence first:

$19-15=4.$

Thus, $d=4.$

So, the first tem $a(1)$ = 15.

The number of last row ( $n$ ) = 30.

Now, to get the number of seat in the 30th row we put formula:

$a(n) = a(1) + d(n-1)$

$a(30)=15+4(30-1)$

$a(30)=15+4\times 29$

$a(30)=15+116$

$a(30)=131$

Therefore, 131 seats are in the 30th row.

4 0

3 years ago