A. As sun peeks, it creates a straight line- sun to tree to shadow, angle=180°
b. During morning, the sun-tree-shadow changes from 180° to 90°, during noon, angle =90°.During sunset the angle changes from 90 to 0°.
c. Acute angles created in afternoon.
d. A right angle would be created at noon.
e. Obtuse angle would be created in morning.
f. Yes, a straight angle would be created at sunrise.
g. When sun is at mid-morning, the angle=45°+90°= 135°
Since the second equation gives a value for a, we can substitute it into the other equation to find a value for B.
Let's substitute b-2 into the first equation wherever there is an a.
a - 3b = 4
(b-2) - 3b = 4
b - 2 - 3b = 4
-2 - 2b = 4
-2b = 6
b = -3
Now let's find a by substituting -3 into either of the equations to find the value of a.
a = b - 2
a = -3 - 2
a = -5
So your solution set is (-5, -3)
Answer:
I think 2600 passwords are possible
25 because there's 5 people so you take 5 times 5
Answer:
- Mar 18: 125
- Mar 19: 318
- Mar 20: 743
- Mar 25: 15,070
Step-by-step explanation:
The six seemingly arbitrary points have no common difference or ratio, so cannot be modeled by a linear or exponential function.
The differences of the differences are not constant at any level, so the only polynomial model is 5th-degree. It is ...
(6n^5 -95n^4 +600n^3 -1825n^2 +2814n -1320)/60
where n = days after Mar 11. (Mar 12 corresponds to n=1.) The domain is n ≥ 1.
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The 5th-degree polynomial increases very fast, but not as fast as an exponential function would.
The values for Mar 12 through Mar 25 are ...
3, 8, 11, 16, 25, 50, 125, 318, 743, 1572, 3047, 5492, 9325, 15070