Answer:
The required polynomial is
.
Step-by-step explanation:
If a polynomial has degree n and
are zeroes of the polynomial, then the polynomial is defined as

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.
According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.
Since 3-3i is zero, therefore 3+3i is also a zero.
Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is


![[a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5Ba%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)

![[i^2=-1]](https://tex.z-dn.net/?f=%5Bi%5E2%3D-1%5D)


Therefore the required polynomial is
.