Answer:
When we have something like:
![\sqrt[n]{x}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D)
It is called the n-th root of x.
Where x is called the radicand, and n is called the index.
Then the term:
![\sqrt[4]{16}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D)
is called the fourth root of 16.
And in this case, we can see that the index is 4, and the radicand is 16.
At the end, we have the question: what is the 4th root of 16?
this is:
![\sqrt[4]{16} = \sqrt[4]{4*4} = \sqrt[4]{2*2*2*2} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%20%5Csqrt%5B4%5D%7B4%2A4%7D%20%20%3D%20%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%7D%20%3D%202)
The 4th root of 16 is equal to 2.
35000, rounding down from five.
Answer:
False. They will be parallel to each other
Answer:
No Solution
Step-by-step explanation:
6 - 3x = 4 - x - 3 - 2x (Given)
6 - 3x = -1 -3x (combine like terms)
7 (addition)
The x cancels each other out so no solution.
Answer:
g(f(x)) = -6x+6.
Step-by-step explanation:
It is given that,
f(x) = -3x + 2 and g(x) = 2x – 5
We need to find g(f(x)).
Put it into g(x).
g(f(x)) = 2(-3x + 2)+2
= -6x+4+2
=-6x+6
Hence, the value of g(f(x)) is -6x+6.
