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enot [183]
3 years ago
10

What is (3 + 12) - 3² + 8 · 2 ÷ 4 ? (please show how/ show work)

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

10

Step-by-step explanation:

(3 + 12) - 3² + 8 · 2 ÷ 4

15 - 9 + 16 : 4

6 + 4

10

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What is the slope-intercept form of the function described by this table? x 1 2 3 4 y −2 −6 −10 −14 Enter your answers in the bo
Olin [163]

Answer:

y=-4x+2

Step-by-step explanation:

we know that

The equation of the line in slope intercept form is equal to

y=mx+b

Step 1

Find the slope m

Let

A(1,-2),B(2.-6)

m=(-6+2)/(2-1)=-4

Step 2

Find the value of b

we have

m=-4

A(1,-2)

substitute in the equation of the line

y=mx+b

-2=(-4)(1)+b

-2=-4+b

b=2

The equation in slope intercept form is equal to

y=-4x+2

3 0
2 years ago
How is the graph of y = |x| − 1 different from the parent function f(x) = |x|?
Jlenok [28]

Answer:

Step-by-step explanation:

the graph moves down one unit

if you add/subtract outside the parent function the graph moves up/down

3 0
3 years ago
I need help to solve the system of equation by elimination.<br><br>x - 2y = -10<br>-5x + 4y = 14
Agata [3.3K]
Your answer is an ordered pair (2,6)
3 0
3 years ago
What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard <br>​
kompoz [17]

Answer:

15/24

Step-by-step explanation:

3/4 * 5/6 = 15/24

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5 0
3 years ago
Find the quotient. Simplify if possible -6/10 + (-5/7)
Zepler [3.9K]

Answer: The correct answer is \frac{21}{25}

Step-by-step explanation:

To find a quotient, we need to divide the two numbers. The equation given to us is :

\frac{-6}{10}\div \frac{-5}{7}

To Simplify the above equation and finding out the quotient, we need to divide the above equation, we get:

\Rightarrow \left(\frac{\frac{-6}{10}}{\frac{-5}{7}}\right)

Taking the reciprocal of the denominator and multiplying it with the numerator, we get:

\Rightarrow \frac{-6}{10}\times \frac{7}{-5}\\\\\Rightarrow \frac{42}{50}\\\\\Rightarrow \frac{21}{25}

Hence, the correct answer is \frac{21}{25}

5 0
3 years ago
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