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irga5000 [103]
3 years ago
8

Can you help me with this question??

Mathematics
1 answer:
Charra [1.4K]3 years ago
4 0

9514 1404 393

Answer:

  about 1.4288993 radians

Step-by-step explanation:

The angle to terminal arm A is ...

  ∠A = arctan((-4/5)/(-3/5)) ≈ 4.0688879 radians

The angle to terminal arm B is ...

  ∠B = arctan((-1/√2)/(1/√2)) ≈ 5.4977871 radians

Then the angle between the arms is ...

  5.4977871 -4.0688879 ≈ 1.4288993 . . . radians

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Find its inverse and check your answer. (b) Find the domain and the range of f and
ElenaW [278]

We have the function:

f(x) = 3x / (x + 7)

(a)

We rename the function as: f(x) = y

Then:

y = 3x / (x + 7)

Taking the inverse:

1/y = (x + 7) / 3x

1/y = x/3x + 7/3x

1/y = 1/3 + 7/3x

Solving for x:

1/y - 1/3 = 7/3x

1/x = 3/7y - 1/7 = (3 - y) / 7y

Taking the inverse:

x = 7y / (3 - y)

Then, the inverse function of f is:

f ⁻¹(x) = 7x / (3 - x)

(b)

We know that the division by 0 is undefined in real numbers. From the function f, we have a division by 0 if x = -7, so the domain should be:

Dom_f = {x| x ≠ -7}

For the range, we know that x = -7 is a vertical asymptote of the function f, so this means that the graph never passes across x = -7, but it tends to it on infinity. Then, the range of f is:

Ran_f = All the real numbers

For f ⁻¹(x), we see that for x = 3 there is a division by 0, so this is an asymptote of the function. Then, the domain of f ⁻¹ is:

Dom_f ⁻¹ = {x| x ≠ 3}

Again, as there is an asymptote, the range is:

Ran_f ⁻¹ = All the real numbers

7 0
1 year ago
9/10-3/14_____<br><br> Simplest form
Lera25 [3.4K]
10=2×5 and 14=2×7 so least common denominator will be 2×5×7=70
9/10=63/70
3/14=15/70
So 63/70-15/70=48/70=24/35
3 0
4 years ago
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Answer:

hello

Step-by-step explanation:

your question is not coming clearly

4 0
3 years ago
Events A and B are mutually exclusive. Suppose event A occurs with probability 0.36 and event B occurs with probability 0.31. Co
Alekssandra [29.7K]

Answer:

Events A and B are dependent

Step-by-step explanation:

If A and B are two events such as A and B are dependent then

P(A∩B)  P(A) P(B)

An event A will occur with probability 0.4 that is  

An event B will occur with probability 0.6 that is  

The probability that both A and B will occur is 0.20 that is P(A∩B) = 0.20

Therefore,

P(A∩B)  P(A) P(B)

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events A and B are dependent

4 0
3 years ago
Read 2 more answers
Write a linear function f with the values f(-4) = 0 and f(0) =0 please help
Sergeeva-Olga [200]

f(\stackrel{x_1}{-4})=\stackrel{y_1}{0}\qquad f(\stackrel{x_2}{0})=\stackrel{y_2}{0}~\hfill (\stackrel{x_1}{-4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-4)}}}\implies \cfrac{0}{0+4}\implies \cfrac{0}{4}\implies 0

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{0}(x-\stackrel{x_1}{(-4)})\implies \boxed{y = 0}

6 0
3 years ago
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