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2 years ago

What are the ordered pairs of the solutions for this system of equations

Mathematics

1 answer:

AleksAgata [21]2 years ago

7 0

Answer:

(3, 6); (-3, 18)

Step-by-step explanation:

We equate the 2 expressions in x :-

x^2 - 2x + 3 = -2x + 12

x^2 - 2x + 2x + 3 - 12 = 0

x^2 - 9 = 0

(x - 3)(x + 3) = 0

So x = 3 or -3.

When x = 3, f(x) = -2(3) + 12 = 6.

When x = -3, f(x) = -2(-3) + 12 = 18.

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Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems

Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for $(x_{1},y_{1}) and (x_{2},y_{2})$

Use the distance formula to find the length = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length = $\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\$

length = $\sqrt{80}$

length = 8.94

Use the distance formula to find the width = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width = $\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\$

width = $\sqrt{(-10 )^{2} + (11 )^{2}}\\$

width = $\sqrt{100 + 121}\\$

width = $\sqrt{221}$

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

7 0

3 years ago

J is the midpoint of hk. what is hj, jk, and hk

Lyrx [107]

Hj and jk are the same length line segments ( because the midpoint divides a line into two equal parts)
So hj = jk.

hk is the line segment which has the mid point j. It is the double of hj or jk. It can be the sum of hj and jk.
hj + jk = hk
or
2 * hj = hk
or
2 * jk = hk

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3 years ago

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Luda [366]

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NISA [10]

Answer:

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