All categories

3 years ago

Help me plz, explain it

Mathematics

2 answers:

Darya [45]3 years ago

6 0

The perimeter of a rectangle is found by multiplying the length by 2 and the width by 2 and adding them together.

P = 2L + 2W

Filling in the information given we can find the width:

16.8 = 2(3.6) + 2W

16.8 = 7.2 + 2W

2w = 16.8 - 7.2

2w = 9.6

w = 9.6 / 2

w = 4.8 in.

denis-greek [22]3 years ago

6 0

A rectangle has 2 equal lengths and 2 equal widths. If one length is 3.6 then multiply by 2 = 7.2
So then 16.8 - 7.2 = 9.6
Then divide 9.6 by 2 = 4.8

You might be interested in

270∙7÷9−360÷(20÷5)+(42∙6÷7+14)

mariarad [96]

Answer:

170

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xe^y + ye^z +

LUCKY_DIMON [66]

Answer:

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}$

Step-by-step explanation:

We need to find the directional derivative of the function at the given point in the direction of the vector v.

$f(x, y, z)=xe^{y} + ye^{z} + ze^{x}$ ,point (0, 0, 0) and $v=$

By Theorem: If f is a differentiable function of x , y and z , then f has a directional derivative for any unit vector $\overrightarrow{v} =$ and

$D_{\overrightarrow{u}}f(x,y,z)=f_{x}(x,y,z)u_1+f_{y}(x,y,z)u_2+f_{z}(x,y,z)u_3$

where $\overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}$

since, $v=$

then $\overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}$

$\overrightarrow{u}=< \frac{6}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{-3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}} >$

$\overrightarrow{u}=< \frac{6}{\sqrt{54}},\frac{3}{\sqrt{54}},\frac{-3}{\sqrt{54}} >$

The partial derivatives are

$f_{x}(x,y,z)=e^{y}+ze^{x}$

$f_{y}(x,y,z)=xe^{y}+e^{z}$

$f_{z}(x,y,z)=ye^{z}+e^{x}$

Then the directional derivative is

$D_{\vec{u}}f(x,y,z)=(e^{y}+ze^{x})(\frac{6}{\sqrt{54}})+(xe^{y}+e^{z})(\frac{3}{\sqrt{54}})+(ye^{z}+e^{x})(\frac{-3}{\sqrt{54}})$

so, directional derivative at point (0,0,0)

$D_{\vec{u}}f(0,0,0)=(e^{0}+0e^{0})(\frac{6}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{3}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{-3}{\sqrt{54}})$

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}+\frac{3}{\sqrt{54}}+\frac{-3}{\sqrt{54}}$

$D_{\vec{u}}f(0,0,0)=\frac{6+3-3}{\sqrt{54}}$

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}$

3 0

4 years ago

Find the slope of the line that passes through (10,5) and (3,2).

Colt1911 [192]

The answer is 3/7, 5-2=3 and 10-3=7

5 0

3 years ago

Need help, please I can’t get these wrong!

algol13

Answer:

1: 119 2: 61 3: 61 4: 119 5: 119 6: 61 7: 61

Step-by-step explanation:

Since we know that m & n are parallel we can prove which angles are congruent to angle 8 and which are supplementary

5: 119 (vertical to angle 8)

1: 119 (corresponding angles theorem

2: 61 (linear pair)

3: 61 (vertical to 2)

4: 119 (vertical to 1)

6: 61 (same sided interior angles theorem)

7: 61 (corresponding)

4 0

4 years ago

Read 2 more answers

How many degrees would a kite need to be rotated to carry it onto itself?

Vsevolod [243]

Answer:360 degree angle

A kite does not have rotation symmetry because it would take a full 360 degrees rotation for it to look the same as the original

6 0

4 years ago